7/8(40x^2-16x+32)

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Solution for 7/8(40x^2-16x+32) equation:


x in (-oo:+oo)

(7/8)*(40*x^2-(16*x)+32) = 0

(7/8)*(40*x^2-16*x+32) = 0

7/8*(40*x^2-16*x+32) = 0

40*x^2-16*x+32 = 0

8*(5*x^2-2*x+4) = 0

5*x^2-2*x+4 = 0

DELTA = (-2)^2-(4*4*5)

DELTA = -76

DELTA < 0

8 = 0

7/8*8 = 0

x belongs to the empty set

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